我是android开发的新手。我想使用php mysql和json进行登录验证。

我只处理PHP,MySql和json部分。

如果用户在android应用中输入用户名和密码,则需要使用PHP和Mysql检查用户表,并且需要使用json仅发送状态代码(例如1或0)。

如果用户名和密码匹配,则状态= 1需要发送到android应用编码,否则为0。

状态检查过程需要在Android编码部分中完成。

如果status = 1,并且我需要重定向到android应用中的另一个窗口。

我看到了很多问题,但没有任何帮助。

因此,请帮助我如何将状态从PHP发送到android应用,以及如何获取该状态并在android中进行验证。

#1 楼

我已经为我的项目完成了这段代码。而且效果很好。试试看。

Login2.php

<?php
$un=$_POST['username'];
$pw=$_POST['password'];
//connect to the db

$host="localhost"; // Host name 
$user="root"; // Mysql username 
$pswd=""; // Mysql password 
$db="database_name"; // Database name 
$tbl_name="user_info"; // Table name

$conn = mysql_connect($host, $user, $pswd);
mysql_select_db($db, $conn);
//run the query to search for the username and password the match
//$query = "SELECT * FROM $tbl_name WHERE first_name = '$un' AND password = '$pw'";
$query = "SELECT emp_id FROM $tbl_name WHERE first_name = '$un' AND password = '$pw'";
$result = mysql_query($query) or die("Unable to verify user because : " . mysql_error());
//this is where the actual verification happens
if(mysql_num_rows($result) > 0)
echo mysql_result($result,0);  // for correct login response
else
echo 0; // for incorrect login response
?>


Android的Java代码
login.java

/>使用两个edittext和按钮,然后在按钮上单击以放置此代码。
删除您不希望将用户名,emp_id保存到整个应用程序的saveperference方法。

    @Override
                public void onClick(View v) {
                    // TODO Auto-generated method stub

                    ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>();
                    postParameters.add(new BasicNameValuePair("username", username
                            .getText().toString()));
                    postParameters.add(new BasicNameValuePair("password", password
                            .getText().toString()));
                    // String valid = "1";
                    String response = null;
                    try {
                        // "http://10.0.2.2//Mobile/login2.php"
                        response = CustomHttpClient
                                .executeHttpPost(
                                        "http://10.0.2.2//Mobile/login2.php",
                                        postParameters);
// now in result you will have the response from php file either 0 or 1.                        
result = response.toString();
                        // res = res.trim();
                        result = result.replaceAll("\s+", "");
                        // error.setText(res);

                        if (!result.equals("0")) {
                            SavePreferences("name", "pass", "emp_id", username
                                    .getText().toString(), password.getText()
                                    .toString());
                            Intent in = new Intent(Login.this, MainScreen.class);

                            // LoadPreferences();
                            error.setText("");

                            startActivity(in);
                        }

                        else
                            error.setText("Incorrect Username or Password");

                    } catch (Exception e) {
                        // un.setText(e.toString());
                    }

                }


CustumHttpClient.java

public class CustomHttpClient {
    /** The time it takes for our client to timeout */
    public static final int HTTP_TIMEOUT = 30 * 1000; // milliseconds

    /** Single instance of our HttpClient */
    private static HttpClient mHttpClient;

    /**
     * Get our single instance of our HttpClient object.
     *
     * @return an HttpClient object with connection parameters set
     */
    private static HttpClient getHttpClient() {
        if (mHttpClient == null) {
            mHttpClient = new DefaultHttpClient();
            final HttpParams params = mHttpClient.getParams();
            HttpConnectionParams.setConnectionTimeout(params, HTTP_TIMEOUT);
            HttpConnectionParams.setSoTimeout(params, HTTP_TIMEOUT);
            ConnManagerParams.setTimeout(params, HTTP_TIMEOUT);
        }
        return mHttpClient;
    }

    /**
     * Performs an HTTP Post request to the specified url with the
     * specified parameters.
     *
     * @param url The web address to post the request to
     * @param postParameters The parameters to send via the request
     * @return The result of the request
     * @throws Exception
     */
    public static String executeHttpPost(String url, ArrayList<NameValuePair> postParameters) throws Exception {
        BufferedReader in = null;
        try {
            HttpClient client = getHttpClient();
            HttpPost request = new HttpPost(url);
            UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(postParameters);
            request.setEntity(formEntity);
            HttpResponse response = client.execute(request);
            in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));

            StringBuffer sb = new StringBuffer("");
            String line = "";
            String NL = System.getProperty("line.separator");
            while ((line = in.readLine()) != null) {
                sb.append(line + NL);
            }
            in.close();

            String result = sb.toString();
            return result;
        } finally {
            if (in != null) {
                try {
                    in.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        }
    }

    /**
     * Performs an HTTP GET request to the specified url.
     *
     * @param url The web address to post the request to
     * @return The result of the request
     * @throws Exception
     */
    public static String executeHttpGet(String url) throws Exception {
        BufferedReader in = null;
        try {
            HttpClient client = getHttpClient();
            HttpGet request = new HttpGet();
            request.setURI(new URI(url));
            HttpResponse response = client.execute(request);
            in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));

            StringBuffer sb = new StringBuffer("");
            String line = "";
            String NL = System.getProperty("line.separator");
            while ((line = in.readLine()) != null) {
                sb.append(line + NL);
            }
            in.close();

            String result = sb.toString();
            return result;
        } finally {
            if (in != null) {
                try {
                    in.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        }
    }
}


评论


现在就试试。让我知道是否还有其他错误。

– Brohi先生
2012年11月12日上午10:15

这对我帮助很大。但是,在这段代码中,您没有正确使用json概念。你能用json ..做吗?

–user1802184
2012年11月16日下午4:32

#2 楼

您的android客户端必须在您的PHP脚本中进行Http发布,以返回状态代码。您的脚本会将该请求视为其他任何发布请求。客户端从服务器接收结果,并进行所需的计算。

#3 楼

只需遵循此代码,我认为它的工作就很好...

$email = isset($_REQUEST['email'])?urldecode($_REQUEST['email']):"";
$passwd= isset($_REQUEST['passwd'])?urldecode($_REQUEST['passwd']):"";
if($email==""||$passwd=="" )
{
$return_data['status'] = 0;

}
else
{
  $user_info="select id from table name WHERE email=$emailAND passwd=$passwd";
    if($user_info)
      {
       $return_data['status'] = 1;
      }
     else
    {
     $return_data['status'] = 0;
    }
}
echo json_encode($return_data);


评论


嗨,我已经发送了类似echo echo json_encode($ return_data);的信息,在此之后,如何将此状态值获取到Android App中。

–user1802184
2012年11月6日在7:14

您只需要调用网络服务,传递电子邮件和passwd的值...之后,您就会收到响应...

– heart_hacker
2012年11月6日7:19

isset($ _ REQUEST ['email'])?urldecode($ _ REQUEST ['email']):“”; ,您能否说出此功能的确切作用?

–user1802184
2012年11月6日7:24

如果您传递的电子邮件值包含任何特殊字符,请使用urldecode避免该字符.....只需在webservices的帮助下传递您的电子邮件和密码http post方法。

– heart_hacker
2012年11月6日7:48