示例:
链接:
www.thisismylink.com/postName.php
参数:
id = 13
name = Jack
最简单的方法是什么?
我什至不想阅读响应。我只想发送该文件,以通过PHP文件对数据库进行更改。
#1 楼
在Swift 3和更高版本中,您可以:let url = URL(string: "http://www.thisismylink.com/postName.php")!
var request = URLRequest(url: url)
request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
request.httpMethod = "POST"
let parameters: [String: Any] = [
"id": 13,
"name": "Jack & Jill"
]
request.httpBody = parameters.percentEncoded()
let task = URLSession.shared.dataTask(with: request) { data, response, error in
guard let data = data,
let response = response as? HTTPURLResponse,
error == nil else { // check for fundamental networking error
print("error", error ?? "Unknown error")
return
}
guard (200 ... 299) ~= response.statusCode else { // check for http errors
print("statusCode should be 2xx, but is \(response.statusCode)")
print("response = \(response)")
return
}
let responseString = String(data: data, encoding: .utf8)
print("responseString = \(responseString)")
}
task.resume()
其中:
extension Dictionary {
func percentEncoded() -> Data? {
return map { key, value in
let escapedKey = "\(key)".addingPercentEncoding(withAllowedCharacters: .urlQueryValueAllowed) ?? ""
let escapedValue = "\(value)".addingPercentEncoding(withAllowedCharacters: .urlQueryValueAllowed) ?? ""
return escapedKey + "=" + escapedValue
}
.joined(separator: "&")
.data(using: .utf8)
}
}
extension CharacterSet {
static let urlQueryValueAllowed: CharacterSet = {
let generalDelimitersToEncode = ":#[]@" // does not include "?" or "/" due to RFC 3986 - Section 3.4
let subDelimitersToEncode = "!$&'()*+,;="
var allowed = CharacterSet.urlQueryAllowed
allowed.remove(charactersIn: "\(generalDelimitersToEncode)\(subDelimitersToEncode)")
return allowed
}()
}
这将检查两个基本网络错误以及高级HTTP错误。这也可以正确地对查询的参数进行转义。
请注意,我使用了
name
的Jack & Jill
,以说明x-www-form-urlencoded
的正确name=Jack%20%26%20Jill
结果,该结果已“百分比编码”(即,空格替换为%20
,值中的&
替换为%26
)。有关Swift 2演绎的信息,请参见此答案的先前版本。
评论
仅供参考,如果您要执行实际请求(包括转义百分比,创建复杂请求,简化响应解析),请考虑使用AFNetworking作者的AlamoFire。但是,如果您只想执行简单的POST请求,则可以使用上面的代码。
–Rob
2014年10月14日在16:07
谢谢Rob,那正是我想要的!只不过是一个简单的POST。好答案!
–愤怒
2014年10月14日下午16:58
在这方面,Alamofire并不比URLSession好,也没有比URLSession差。所有网络API本质上都是异步的,应该也是如此。现在,如果您正在寻找其他优雅的方式来处理异步请求,则可以考虑将它们(URLSession请求或Alamofire请求)包装在异步的自定义Operation子类中。或者,您可以使用一些Promise库,例如PromiseKit。
–Rob
'18 Apr 6在0:48
@DeepBlue-我明白您的意思,但我不同意。如果有问题,让自己静默失败是一个非常糟糕的主意。也许您可以警惕let url = ... else {fatalError(“ Invalid URL”)},但这在语法上毫无用处。您正在编写大量错误处理代码,而不是最终用户运行时问题,而是编程问题错误。类比是隐式展开的@IBOutlet引用。您是否为所有网点写了吨警戒标签= ...代码?不,那太傻了。同样在这里。
–Rob
19年5月24日在7:40
不要误会我的意思。如果某些事情不是立即显而易见的,或者由于程序员无法控制的原因而失败(例如解析JSON响应和/或处理网络错误),那么使用强制解包运算符是一个巨大的错误。绝对安全地拆开那些包装。但是对于@IBOutlet之类的内容或该URL示例,则添加这种语法噪音IMHO适得其反。而且,要使用只返回的else子句进行保护,隐藏任何潜在的问题,是一个非常糟糕的主意。
–Rob
19年5月24日在7:41
#2 楼
Swift 4及更高版本@IBAction func submitAction(sender: UIButton) {
//declare parameter as a dictionary which contains string as key and value combination. considering inputs are valid
let parameters = ["id": 13, "name": "jack"]
//create the url with URL
let url = URL(string: "www.thisismylink.com/postName.php")! //change the url
//create the session object
let session = URLSession.shared
//now create the URLRequest object using the url object
var request = URLRequest(url: url)
request.httpMethod = "POST" //set http method as POST
do {
request.httpBody = try JSONSerialization.data(withJSONObject: parameters, options: .prettyPrinted) // pass dictionary to nsdata object and set it as request body
} catch let error {
print(error.localizedDescription)
}
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
request.addValue("application/json", forHTTPHeaderField: "Accept")
//create dataTask using the session object to send data to the server
let task = session.dataTask(with: request as URLRequest, completionHandler: { data, response, error in
guard error == nil else {
return
}
guard let data = data else {
return
}
do {
//create json object from data
if let json = try JSONSerialization.jsonObject(with: data, options: .mutableContainers) as? [String: Any] {
print(json)
// handle json...
}
} catch let error {
print(error.localizedDescription)
}
})
task.resume()
}
评论
我的代码出现以下错误:“数据格式不正确,因此无法读取”。
–applecrusher
16 Dec 13'在16:28
我认为您收到的字符串格式的响应可以验证吗?
– Suhit Patil
16 Dec 14'2:41
我认为此解决方案中的问题是您将参数传递为json序列化,并且Web服务将其作为formdata参数
–愤怒
17年2月15日在11:46
是的,在解决方案中参数为json,请与服务器检查是否需要表单数据,然后更改内容类型,例如request.setValue(“ application / x-www-form-urlencoded”,forHTTPHeaderField:“ Content-Type”)
– Suhit Patil
17年2月15日在12:51
对于多部分参数,请使用let boundaryConstant =“ --V2ymHFg03ehbqgZCaKO6jy--”; request.addvalue(“ multipart / form-data boundary =(boundaryConstant)”,对于HTTPHeaderField:“ Content-Type”)
– Suhit Patil
17-2-15在13:05
#3 楼
对于寻求在Swift 5中对POST请求进行编码的干净方法的人。您无需手动添加百分比编码。
使用
URLComponents
创建GET请求URL。然后使用该URL的query
属性正确获取转义百分比的查询字符串。let url = URL(string: "https://example.com")!
var components = URLComponents(url: url, resolvingAgainstBaseURL: false)!
components.queryItems = [
URLQueryItem(name: "key1", value: "NeedToEscape=And&"),
URLQueryItem(name: "key2", value: "vålüé")
]
let query = components.url!.query
query
将是正确转义的字符串:key1 = NeedToEscape%3DAnd%26&key2 = v%C3%A5l%C3%BC%C3%A9
现在您可以创建请求并将查询用作HTTPBody:
var request = URLRequest(url: url)
request.httpMethod = "POST"
request.httpBody = Data(query.utf8)
现在您可以发送请求。
评论
在各种示例之后,只有这适用于Swift 5。
–夹竹桃
1月7日9:19
我提出了GET请求,但我不知道POST请求如何?如何将参数传递到httpBody或我需要它?
– Mertalp Tasdelen
1月31日22:30
智能解决方案!感谢您分享@pointum。我确定Martalp不再需要答案了,但是对于其他阅读的人,上面的请求是POST。
– Vlad Spreys
5月13日22:04
#4 楼
这是我在日志记录库中使用的方法:https://github.com/goktugyil/QorumLogs此方法填充Google Forms中的html表单。
var url = NSURL(string: urlstring)
var request = NSMutableURLRequest(URL: url!)
request.HTTPMethod = "POST"
request.setValue("application/x-www-form-urlencoded; charset=utf-8", forHTTPHeaderField: "Content-Type")
request.HTTPBody = postData.dataUsingEncoding(NSUTF8StringEncoding)
var connection = NSURLConnection(request: request, delegate: nil, startImmediately: true)
评论
什么是application / x-www-form-urlencoded您要设置什么?
–蜂蜜
17 Mar 24 '17 at 20:09
用于在请求正文中传递数据@Honey
–阿赫拉夫
18/09/10在10:57
#5 楼
let session = URLSession.shared
let url = "http://...."
let request = NSMutableURLRequest(url: NSURL(string: url)! as URL)
request.httpMethod = "POST"
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
var params :[String: Any]?
params = ["Some_ID" : "111", "REQUEST" : "SOME_API_NAME"]
do{
request.httpBody = try JSONSerialization.data(withJSONObject: params, options: JSONSerialization.WritingOptions())
let task = session.dataTask(with: request as URLRequest as URLRequest, completionHandler: {(data, response, error) in
if let response = response {
let nsHTTPResponse = response as! HTTPURLResponse
let statusCode = nsHTTPResponse.statusCode
print ("status code = \(statusCode)")
}
if let error = error {
print ("\(error)")
}
if let data = data {
do{
let jsonResponse = try JSONSerialization.jsonObject(with: data, options: JSONSerialization.ReadingOptions())
print ("data = \(jsonResponse)")
}catch _ {
print ("OOps not good JSON formatted response")
}
}
})
task.resume()
}catch _ {
print ("Oops something happened buddy")
}
#6 楼
这里的所有答案都使用JSON对象。这给我们Codeigniter控制器的$this->input->post()
方法带来了问题。
CI_Controller
无法直接读取JSON。我们使用此方法无需JSON
func postRequest() {
// Create url object
guard let url = URL(string: yourURL) else {return}
// Create the session object
let session = URLSession.shared
// Create the URLRequest object using the url object
var request = URLRequest(url: url)
// Set the request method. Important Do not set any other headers, like Content-Type
request.httpMethod = "POST" //set http method as POST
// Set parameters here. Replace with your own.
let postData = "param1_id=param1_value¶m2_id=param2_value".data(using: .utf8)
request.httpBody = postData
// Create a task using the session object, to run and return completion handler
let webTask = session.dataTask(with: request, completionHandler: {data, response, error in
guard error == nil else {
print(error?.localizedDescription ?? "Response Error")
return
}
guard let serverData = data else {
print("server data error")
return
}
do {
if let requestJson = try JSONSerialization.jsonObject(with: serverData, options: .mutableContainers) as? [String: Any]{
print("Response: \(requestJson)")
}
} catch let responseError {
print("Serialisation in error in creating response body: \(responseError.localizedDescription)")
let message = String(bytes: serverData, encoding: .ascii)
print(message as Any)
}
// Run the task
webTask.resume()
}
现在您的CI_Controller将能够使用
param1
和param2
获得$this->input->post('param1')
和$this->input->post('param2')
#7 楼
@IBAction func btn_LogIn(sender: AnyObject) {
let request = NSMutableURLRequest(URL: NSURL(string: "http://demo.hackerkernel.com/ios_api/login.php")!)
request.HTTPMethod = "POST"
let postString = "email: test@test.com & password: testtest"
request.HTTPBody = postString.dataUsingEncoding(NSUTF8StringEncoding)
let task = NSURLSession.sharedSession().dataTaskWithRequest(request){data, response, error in
guard error == nil && data != nil else{
print("error")
return
}
if let httpStatus = response as? NSHTTPURLResponse where httpStatus.statusCode != 200{
print("statusCode should be 200, but is \(httpStatus.statusCode)")
print("response = \(response)")
}
let responseString = String(data: data!, encoding: NSUTF8StringEncoding)
print("responseString = \(responseString)")
}
task.resume()
}
评论
可能需要更新Swift 3/4才能使用URLRequest
–亚当·韦尔(Adam Ware)
19年1月20日,下午3:34
评论
stackoverflow.com/a/48306950/6898523